What is a point-slope equation of the line with slope –13 that goes through the point (5, 7)?

a. y – 7 = –13(x – 5)
b. y – 5 = –13(x – 7)
c. y + 5 = –13(x + 7)
d. y + 7 = –13(x + 5)

answer is A. y – 7 = –13(x – 5)

using y - y1 = m(x - x1) with m = -13, y1 = 7, x1 = 5

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?