Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively?

There is no given data table but based on the question, the reaction is
xy <=> x + y
If we let M as the initial concentration of xy and c as the in the concentration after the dissociation, then we can use the ICE method
    xy   <=>   x    +   y
I    M
C  -c            c         c

E  M-c          c         c

Solve for c using
Kc = c(c) / (M - c)
And the concentration of the xy, x, and y can then be determined

step-by-step explanation:

yes it is1. move over 2 points on the x-axis2. move over 2 points on the y-axis

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post