Astudent works two different jobs. at the first job, they earn $8.50 per hour working at a fast
food restaurant. at their second job, they are paid $25 to take care of landscaping at their
neighbor’s house once a week. write a function rule showing that the amount the student
earns, (ℎ), depends on the number of hour worked, ℎ, and use it to determine how much the
student earns each week. then evaluate the expression to determine how much the student will
earn next week if they are scheduled to work 12 hours and 45 minutes at the restaurant.
a. (ℎ) = (8.5 + 25)ℎ; $417.08
b. (ℎ) = 8.5ℎ + 25; $130.83
c. (ℎ) = 25ℎ + 8.5; $327.25
d. (ℎ) = 8.5ℎ + 25; $133.38

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.