Mathematics, 04.02.2020 06:44 isophk
What is the point-slope equation of the line through the point (β5, 5) that is perpendicular to the line whose equation is 5x = 3y?
a. y β 5 = 5/3(x + 5)
b. y β 5 = β3/5(x + 5)
c. y β 5 = 3/5(x + 5)
d. y β 5 = β5/3(x + 5)
Answers: 1
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