Find the two numbers whose sum is 24 and whose product is as large as possible.
( show your work, no guess)!

Let, the numbers are: x, (24-x)
Let, P(x) denote their products. Then, we have:
P(x) = x(24-x) = 24x - x²
P'(x) = 24-2x
P''(x) = -2

Now, P'(x) = 0 ⇒ x = 12
Also, 
P''(12) = -2 < 0

So, By second derivative test, x = 12 is the point of local maxima of p. Hence the product of the numbers is the maximum when the numbers are 12 and (24-12) = 12

So, In short that numbers would be 12,12

Hope this helps!

7.3

step-by-step explanation:

81+30=111180 minus 111=691/2×19=9.569÷9.5=7.263157895~7.3