Fyi everyone, random231 is awesome

for a craft project, four students each chose three pieces of wire from a box.

don’s wires measure 3 inches, 5 inches, and 12 inches.
margo’s wires measure 6 inches, 8 inches, and 14 inches.
sonji’s wires measure 12 inches, 8 inches, and 17 inches.
liam’s wires measure 16 inches, 8 inches, and 27 inches.

which student chose pieces that can be used to construct a triangle?

a. don
b. margo
c. sonji
d. liam

C. Sonji

Step-by-step explanation:

Since, a triangle is possible if the sum of any two sides is greater than third side,

The measure of Don’s wires,

3 inches, 5 inches and 12 inches

Since, 3 + 5 < 12  

Thus, by the above statement we can not make a triangle with The measure of Don’s wires.

The measures of Margo's wires,

6 inches, 8 inches and 14 inches,

Since, 6 + 8 = 14,

⇒ we can not make a triangle with The measure of Margo's wires.

The measures of Sonji's wires,

12 inches, 8 inches, and 17 inches,

12 + 8 > 17,

8 + 17 > 12

12 + 17 > 8

⇒ we can make a triangle with the measure of Sonji's wires.

The measures of Liam’s wires,

16 inches, 8 inches, and 27 inches

16 + 8 < 27

⇒ we can not make a triangle with The measure of Liam’s wires.

Hence, option 'C' is correct.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~