Find the value of a. sin 120 degrees b. tan 150 degrees c. cos (-135 degrees) d. sec 300 degrees e. sin 240 - cos 330 degrees

A) sin 120=sin (180-60)=sin 60= (It lies on second quadrant where sin is +ve)
B)  tan (150)=tan(180-30)=-tan30=(It lies on second quadrant where tan is -ve)
C) cos (-135)=cos (135)=cos (180-45)=-cos (45)=(It lies on second quadrant where cos is -ve)
D) sec (300)=sec (360-60)=sec(60)=2 (It lies on fourth quadrant where sec is +ve)
E) sin (240)=sin(180-(-60))=sin(-60)=-sin (60)=
(It lies on third quadrant where sin is -ve)
 F) cos (330)=cos(360-30)=cos(30)=
(It lies on fourth quadrant where cos is +ve)
sin (240)- cos (330)= 

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