Find the volume and solve the application.

a mason is putting in the foundation for a wall. his assistant digs a trench in roughly the shape of a rectangular solid measuring 50 ft. in length, 12 inches deep along both sides, and 12 inches wide at the top and bottom. how many cubic feet of earth did he remove (to the nearest tenth)?

cubic feet.

The volume of cuboid is 50 ft³, therefore he remove 50 ft³.

Step-by-step explanation:

The shape of foundation is a cuboid.

The length is 50 ft, width is 12 inches and depth is 12 inches.

We know that

1 ft = 12 inches

So, the width is 1 ft and depth(height) is 1 ft.

The volume of a cuboid is

Since the volume of cuboid is 50 ft³, therefore he remove 50 ft³.

could

step-by-step explanation:

u send me a picture of ur work

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!