What is the equation of the line that passes through points(-3, 0.5) and (3, -0.5) a. y= -1/6× b. y= -6× c. y= -1/6× + 1 d. y= -6× - 17.5

(-3,0.5)(3,-0.5)
slope = (-0.5 - 0.5) / (3 - (-3) = -1/6

y = mx + b
slope(m) = -1/6
use either of ur points (-3,0.5)...x = -3 and y = 0.5
now we sub and find b, the y int
0.5 = -1/6(-3) + b
0.5 = 1/2 + b
1/2 - 1/2 = b
0 = b

so ur equation is : y = -1/6x

Answer d; a supplementary angle = 180°, so if that angle = 150°, y would = 30°.