What is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?

For the answer to the question on what is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?
the vertex = (5,4) 
p = 2 
4*2(y-4) = (x-5)^2 
y = (1/8)(x-5)^2 + 4

I hope my answer helped. Have a nice day!

(1/x + 1)^2 + 6 (1/x + 1) +5