Find the 3rd term of an arithmetic sequence with t2= 9/2 and t5= 6

Well a simply way is to look at the problem as

Term 1 | 2 | 3 | 4 | 5
Value | 9/2 | | | 6

There are 3 terms from 2 to 5 and the value increases 6 - 9/2 = 3/2 so the common difference is 3/2 divided by 3 so the common difference is 1/2 so to find the 3rd term add 1/2 to the 2nd term the pattern is each term is increasing by 1/2.. or 1/2 is added to the previous term. 

11123355543321112345566444

11/36 is .305 repeating