Akicker kicks a football toward the opponent's goal line during a game. the ball begins it's flight with an initial velocity of 100 feet per second when it is kicked at a height of 3 feet by the kicker. to the nearest foot, what is the maximum height the ball will reach? use h(t)=_16t^2+100t+3

Maximum height reached = 159.25 feet

Step-by-step explanation:

We have the equation h(t)=-16t²+100t+3

At maximum height derivative is zero.

That is

Substituting t = 3.125 s in h(t)=-16t²+100t+3

Maximum height

         h(3.125) = -16 x 3.125²+100 x 3.125 + 3 = 159.25 feet

Maximum height reached = 159.25 feet

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