Find the equation of a line perpendicular to y - 3x = – 8 that passes through the point
(3, 2). (answer in slope-intercept form)

a) y = -3x + 2
b) y = -3x + 3
c) y = -13x + 2
d) y = -13x + 3

Y - 3x = -8
y = 3x - 8...slope here is 3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -1/3.

y = mx + b
slope(m) = -1/3
(3,2)...x = 3 and y = 2
now we sub and find b, the y int
2 = -1/3(3) + b
2 = -1 + b
2 + 1 = b
3 = b

so ur perpendicular equation is : y = -1/3x + 3