What is the ratio of the area of the inner square to the area of the outer square?

a: (a-b)2=b2/a2

b: a2-b2/a2

c: (a-b)2/(a+b)2

d: (ab)2/(a+b)2

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

Thus the area of the inner square = (side)²

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

Thus, the area of the outer square = (side)²

Hence, the ratio of the area of the inner square to the area of the outer square

I got this fraction:

frac{(a-b)^2+b^2}{a^2}

(I got the answer correct)

Hope this is helpful :)

Step-by-step explanation:

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

answer by yourhope:

hi! : )

a farmer that lived in ancient egypt would most likely be barried in the sand, in the desert!

: )