![\frac{1}{ x^{ \frac{-3}{6} } } = \frac{1}{ x^{ \frac{-1}{2} } } = \frac{1}{ x^{-\frac{1}{2} } } \\ \\ x^{-a} = \frac{1}{ x^{a} } \\ \\ \frac{1}{ x^{-a} } = x^{a} \\ \\ \frac{1}{ x^{-\frac{1}{2} } } = x^{\frac{1}{2} } \\ \\ x^{\frac{a}{b} }= \sqrt[b]{ x^{a} } \\ \\ x^{\frac{1}{2} } = \sqrt{x} \\ \\ \\ \frac{1}{ x^{ \frac{-3}{6} } }= \sqrt{x}](/tpl/images/0424/1259/554f4.png)
.![x^{a/b} = \sqrt[b]{ x^{a} } \\ x^{a}* x^{b} = x^{a+b} \\ \\ \\ \sqrt{x} * \sqrt[4]{x} = x^{1/2} *x ^{1/4} = x^{1/2 + 1/4} = x^{2/4+1/4} = x^{3/4}](/tpl/images/0424/1259/5d7f7.png)
![\sqrt[3]{ x^{2} }](/tpl/images/0424/1259/8bf00.png)
![\frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ x^{a/b} = \sqrt[b]{ x^{a} } \\ \\ \\ \frac{ x^{5/6} }{ x^{1/6} } =x^{5/6-1/6} = x^{4/6} = x^{2/3} = \sqrt[3]{ x^{2} }](/tpl/images/0424/1259/04ad4.png)
![\sqrt[b]{ x^{a} }= x^{a/b} \\ \\ \sqrt[4]{ x^{3} } = x^{3/4}](/tpl/images/0424/1259/64070.png)
![\sqrt[b]{ x^{a} }= x^{a/b} \\ \\ x^{a}* x^{b} = x^{a+b} \\ \\ 10 \sqrt{ x^{5}}* x^{4} * x^{2} =10* x^{5/2} *x^{4} * x^{2} =10* x^{5/2+4+2} =10 x^{17/2}](/tpl/images/0424/1259/c8771.png)
Ineed and explanations with these 5 questions.
question 1
is the expression x^3*...
Mathematics, 18.12.2019 10:31 andrewsaul04
Ineed and explanations with these 5 questions.
question 1
is the expression x^3*x^3*x^3equivalent to x^(3*3*3)? why or why not? explain your reasoning.
no because the law of exponents
question 2
rewrite in simplest radical form
1/)/6)
show each step of your process.
question 3
rewrite in simplest rational exponent form √x • 4√x. show each step of your process.
question 4
rewrite in simplest radical form
x^(5/6)/x^(1/6)
show each step of your process.
question 5
which of the following expressions are equivalent? justify your reasoning.
4√x3
1/x^(-1)
10√x5•x4•x2
x^(1/3)*x^(1/3)*x^(1/3)
Answers: 2
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