Aquadratic equation is shown below:

9x2 - 36x + 36 = 0

part a: describe the solution(s) to the equation by just determining the discriminant. show your work. (3 points)

part b: solve 2x2 - 9x + 7 = 0 using an appropriate method. show the steps of your work and explain why you chose the method used.(4 points)

For part A:
9x² - 36x + 36 = 0 
9(x² - 4x + 4) = 0 
9(x-2)(x-2) = 0 
Radicand = Discriminant = 36² - 4(9)(36) = 0 
there is 1 real zero that repeats itself)

zero is x=2. 

Use factoring. Factors of 7 are 1 and 7 
2x²-9x+7 = 0

(2x-7)(x-1) = 0 
2x-7 = 0              (x-1)=0 
2x = 7x=1 
x = 7/2 
Your solutions are x = 1 and x = 7/2 

I hope my answers helped you