Not hard, just confusing.. δabc is reflected across the x-axis and then translated 4 units up to create δa′b′c′. what are the coordinates of the vertices of δa′b′c′ ?

a′(-3, 3), b′(-1, 1), c′(-2, 3)

a′(3, -3), b′(1, -1), c′(2, -3)

a′(3, -5), b′(1, -7), c′(3, -5)

a′(-3, 3), b′(-1, 1), c′(-2, -3)

Correct answer is A.

The reflection across the x-axis changes the sign of the y-coordinate of the point, while the x-coordinate remains the same.

A(-3, 1)  A''(-3, -1)
B(-1, 3)  B''(-1, -3)
C(-2, 1)  C''(-2, -1)

Translation 4 units up increases the y-coordinate for 4, while the x-coordinate remains the same.

A''(-3, -1)  A'(-3, 3)
B''(-1, -3)  B'(-1, 1)
C''(-2, -1)  C'(-2, 3)

Ithink if im not mistaking b is -3 but im not a 100% sude