Regular hexagon abcdef is inscribed in a circle with a radius of 2 units.
find measure of central angle agf
apothem a=gh
side length s=
perimeter p=
hexagon area a=

For the triangle with side lengths equal to the radius of the circle is a equilateral.
so all the angles are 60 degrees

side lengths are the same as the radius as shown in the diagram.
so s = 2units

p = 2 x #ofSides
   = 2 x 8 = 16

area of a hexagon formula proof and formula itslef is sligtly complicated.
Instead we can find the area of 1 triangle, and then multiply it by 6, since a hexagon is made up of these 6 triangles

area of triangle = 2x2 /2 = 2

2 x 6  = 12units^2

Answer\ __o_o__/ lil i don’t kniw

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12