Write the equation of a line perpendicular to 9x+8y=3 that passes through the point (8,-7). type an equation using slope- intercept form or using the given point in point- slope form. use integers or simplified fractions for any numbers in the equation.

9x + 8y = 3
8y = -9x + 3
y = -9/8x + 3/8...slope here is -9/8. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the perpendicular slope is 8/9 (see how I flipped the slope and changed the sign)

y = mx + b
slope(m) = 8/9
(8,-7)x = 8 and y = -7
now we sub and find b, the y int
-7 = 8/9(8) + b
-7 = 64/9 + b
-7 - 64/9 = b
-63/9 - 64/9 = b
-127/9 = b

so ur equation is : y = 8/9x - 127/9

You would plot 83 on the 83 line and you would plot -113 on the -113 line.