The critical points are where the slope is 0 take the derivitive f'(x)=2x-2
find where it equals 0 0=2x-2 2=2x 1=x at x=1 sub that back into original function to find the y value of the critical point f(1)=1^2-2(1)+7 f(1)=1-2+7 f(1)=-1+7 f(1)=6
the point is (1,6) D is answer
Answer from: Quest
answer: b.
step-by-step explanation:
the y coordinate for point b is 0, and answer b is the only one with that y coordinate.
Answer from: Quest
2(2x + 3) = -4 + 2(2x + 5)
4x + 6 = -4 + 4x + 10
4x + 6 = 4x + 6
4x - 6 + 6 = 4x - 6 + 6
4x = 4x
x = x
unlimited solutions.
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