I uploaded the answer to a file hosting below

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation:

hi i’m going tomorrow morning and i can come over and you out with this stuff for me haha ya day is going crazy and i’ll tell you what i’m talking about you don’t wanna go do you think i’m going to be a good friend i just don’t know how much you mean about the stuff you want to do and stuff you know i just want you and you know that i’m going crazy i don’t think i’m going crazy about going tomorrow and i’ll tell ya hey i don’t think i’m going crazy about going tomorrow and i’ll tell you what i’m done