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Mathematics, 21.06.2019 20:30
Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [β1, 1] no, f is continuous on [β1, 1] but not differentiable on (β1, 1). no, f is not continuous on [β1, 1]. yes, f is continuous on [β1, 1] and differentiable on (β1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.
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Mathematics, 21.06.2019 21:00
Solve this problem! extra ! 3025/5.5 = a/90.75 / = fraction
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Mathematics, 21.06.2019 22:30
Solve for x. β3/4(x+2)=6 enter your answer in the box
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Give f(x)=5x-1, g(x)=3^x-9 what is g(x)-f(x)...
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