1. The range of guest on New Year's Eve was 15> 2. About 50% of Thanksgiving dinners had 17 or more people.

3. Everyone had at least one guest over for dinner at Thanksgiving.

4. The IQR of Thanksgiving dinner was 20.

5. The median number of people at New Years' Eve dinner was 15.

6. Three-fourths of New Years' Eve dinners had five or more people.

1.False

2. True

3.) True

4. False

5.) False

6.) True

Step-by-step explanation:

1.)

Range = maximum - minimum

New year's eve :

Maximum = 22 ; minimum = 3

Range = 22 - 3 = 19

2.)

Median for Thanksgiving = 17

50% up to 17 ;hence the remaining 50% is also 17 and above

4.)

IQR for Thanksgiving

Q3 - Q1

23 - 12 = 11

5.)

The median number of people at new year's eve for dinner was 7 (line in between the box)

6.)

3/4th of new year eve's dinner = Q3 = 15

1/4 = Q1 ; have up to 5 people

Therefore ; the remaining (1 - 1/4) = 3/4 have 5 and above

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.