The seagull population on a small island in the Atlantic Ocean can be calculated using the formula P(t) = 5.3/11/?, where P is the population in hundred thousands, and t is in years. What will the seagull

population on the island be after 5 years? (Round to the nearest tenth.)

a. about 41.6 hundred thousand

c. about 172.4 hundred thousand

about 3.7 x 10' hundred thousand d. about 66.5 hundred thousand

The correct relation for the sea gull population is: P(t) = 5.3t^(11/7)

d. about 66.5 hundred thousand

Step-by-step explanation:

Given that :

P(t) = 5.3t^(11/7)

Population, P is in hujdred thousand ; t = number of years

Population after 5 years ;

t = 5

P(5) = 5.3 * 5^(11/7)

P(5) = 5.3 * 5^1.5714285

P(5) = 5.3 * 12.542422

P(5) = 66.474840

P(5) = 66.5 (approximately)

Hence, population after 5 years will be about 66.5 hundred thousand.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.