Question 14Evaluate the cumulative distribution function, F, for the given random variable, X, at specified values; also determine the requested probabilities. f left-parenthesis x right-parenthesis equals left-parenthesis 729divided by 91right-parenthesis left-parenthesis 1 divided by 9right-parenthesis Superscript x, Give exact answers in form of fraction. Upper F left-parenthesis 1 right-parenthesis equalsUpper F left-parenthesis 2 right-parenthesis equalsUpper F left-parenthesis 3 right-parenthesis equals(a) Upper P left-parenthesis Upper X less-than-or-equal-to 1.5 right-parenthesis equals(b) Upper P left-parenthesis Upper X less-than-or-equal-to 3 right-parenthesis equals(c) Upper P left-parenthesis Upper X greater-than 2 right-parenthesis equals(d) Upper P left-parenthesis 1 less-than Upper X less-than-or-equal-to 2 right-parenthesis equals

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

pls mark as brainliest

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.