The graph of quadratic function f(x) has a minimum at (-2,- 3 and passes through the point (2, 13). The functio g(x) is represented by the equation g(x)= -(x+2)(x-3)
How much greater is the y-intercept of g(x) than f(x)?

Step-by-step explanation:

hello :  

the vertex -form of quadratic function f(x) is : f(x) = a(x+b)²+c

the vertex : (- b , c )  

means : (-2,-3)   so :  -b = -2   and  c = - 3      so  :  b =2  and  c = -3

f(x) = a(x+2)²-3

calculate : a  

the graph  passes through the point (2, 13) : f(2)=13

means : a(2+2)²-3 = 13

16a - = 13

16a = 16   so : a = 1

f(x) is represented by the equation f(x) = (x+2)²-3

The graph of  f(x) color red  and g(x) blue

is the y-intercept when g(x) greater g(x) than f(x) is when x=0  so : y = 6

the solution is h=10 because you add 9 to each side of the equation.

the answer is d. 75%