What is the reciprocal of tanB in the triangle below? Right triangle A B C is shown. C is the right angle and side A B is the hypotenuse.

Step-by-step explanation:

C is the right angle and AB is the hypotenuse. We still don't have enough information. Suppose C is on your left. and B is above C

That would mean that CB is the adjacent side and CA is the side opposite.

TanB = CA/BC

The reciprocal would be 1/Tan(B) = BC/CA. I believe this is true no matter how A and B are situated.

1/Tan(B) = Cot(B) by the way.

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5