A right angle triangle has sides of lengths (x+5)cm, (x-3) and 9cm

I'm assuming that 9cm is the hypotenuse

of the triangle.

By using Pythagorean's theorem

a²+b²=c²

in this case, c =9

So, (x+5)² + (x-3)² =(x+5)(x+5) + (x-3)(x-3)

=x²+5x+5x+25+x²-3x-3x+9

=2x²+4x+31=81

And by solving the equation, you get two x values, but since you can't have x as a negative figure, the positive figure being 3.9498, x=3.95 (corrected to 3 significant

figures)

Step-by-step explanation:

CarryOnLerning

MarkAsBrainliest

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get