The sum of two consecutive numbers is 477. What are the numbers?
(Let the first number be x.)

158 + 159 + 160 = 477

Step-by-step explanation:

Here we will use algebra to find three consecutive integers whose sum is 477. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 477. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 477

Here we will use algebra to find three consecutive integers whose sum is 477. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 477. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 477

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 477

3X + 3 = 477

3X + 3 - 3 = 477 - 3

3X = 474

3X/3 = 474/3

X = 158

Which means that the first number is 158, the second number is 158 + 1 and the third number is 158 + 2. Therefore, three consecutive integers that add up to 477 are 158, 159, and 160.

158 + 159 + 160 = 477

I hope it will help u dear

ans789

step-by-step explanation:

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.