In AABC, what is AB to the nearest tenth?

AB = 9.5 units

Step-by-step explanation:

Here, we want to find the measure of AB

To do this, we are going to make use of the sine rule

for the sine rule, the ratio of the measure of a side and the sine of the angle that faces the side is a constant value for a triangle

Thus, we have it that; in a triangle ABC

a/sin A = b/sin B = c/sin C

using the triangle given;

we need the measure of the angle at C

The sum of angles in a triangle is 180

thus;

C + 93 + 48 = 180

C = 180 - 93 -48

C = 39 degrees

Now, to get the value of AB;

AB/sin 39 = 15/sin 93

AB = (15 * sin 39)/sin 93

AB = 9.5 units

congruent segments

step-by-step explanation:

idk

step-by-step explanation: