Help guys I only have 18 minutes left

Given:

The equation of a circle is:

To find:

Center and the circumference of the circle.

Solution:

The standard form of a circle is:

        ...(i)

Where, (h,k) is center and r is the radius.

We have,

          ...(ii)

On comparing (i) and (ii), we get

So, the center of the circle is (3,0) and the radius of the circle is .

Now, the circumference of the circle is:

Therefore, the circumference of the circle is about 35.5 units.

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: