At a local college, 101 of the male students are smokers and 909 are non-smokers. Of the female students, 270 are smokers and 630 are non-smokers. A male student and a female student from the college are randomly selected for a
survey. What is the probability that both are non-smokers?
Do not round your answer. (If necessary, consult a list of formulas.)

63% Chance

Step-by-step explanation:

Remember, to find the probability of non smokers, we must find the percentage of both male and female non-smokers, and multiply them together.

So lets take all our data from this word problem first. 101 males are smokers, 909 males are not. 270 females are smokers, 630 are not.

Now, to find the percentage of non-smokers, lets add up the total amout of males, and then divide the amount of non-smokers by that number:

909+10=

1010

Ok now we know the total amount of males. Lets divide the amount of non-smokers my 1010:

909/1010

=

0.9

So this shows you that 90% of males are non-smokers.

Now lets do the same with the females:

630+270

=

900

Ok, now we know the total amount of females. Lets divide the amount of non-smoking females by this number:

630/900

=

0.7

Ok, so now we know that 70% of females are non-smokers.

Here is the final step, multipling the numbers together to find the chances of both genders being non-smokers.(I put the percentages back into decimal form when i multiplied)

0.7x0.9

=

0.63

So now we have our answer. We know that there is a 63% chance that the survey will be about 2 nonsmoking male and females.

Hope this helps!

$32,660

step-by-step explanation:

2 x t divided by n

step-by-step explanation: