Find the GCF of the two numbers, and rewrite the sum of the two numbers using the distributive property. 3 + 15 A) 1(3 + 5) B) 1(3 × 5) C) 3(1 + 5) D) 3(1 × 5)

GCF of the numbers is 3 and it can be written as 3(1+5)

Step-by-step explanation:

Given the expression 3+15

First we need to find their factors

3 = 3×1

15 = 3×5

Since 3 is common to both factors, hence the GCF is 3

Factorize

3+15

= (3×1)+(3×5)

Factoring 3 out

= 3(1+5)

Hence the GCF of the numbers is 3 and it can be written as 3(1+5)

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

idk

step-by-step explanation: