Parallel lines G and H are shown in one grid and parallel lines K and J are shown on the other grid please help

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  B  reflected over y, translated up

Step-by-step explanation:

The left-right reversal means there was a reflection over a vertical line. The only one among the offered choices is the y-axis.

If the lines are reflected over the y-axis, the points on the y-axis don't move. The intercepts would still be 2 and 5 after the reflection.

However, the y-intercepts have moved up 3 units to 5 and 8.

  Lines g and h were reflected over the y-axis and translated up 3 units.

answer B

Step-by-step explanation:

good luck have a nice day

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3