Two triangles each have adjacent sides of length 120 ft and 180 ft. the first triangle has an angle between the two sides of 40°, while the second triangle has an angle between the two sides of 60°.
what is the approximate difference between the areas of the two triangles?

Step-by-step explanation:

To solve this problem, we need to use the definiton of a triangular area but including angles, like the following

(This formula is used in  triangles, where you know two sides and the angle formed).

Where is the angle of the vertex C, which is equivalent to the difference between the other angles.

So, let's find out the area of each triangle:

The difference between areas would be

Therefore, the difference is around 2410.96 square feet.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

yo answer should be 6 if im not mistaken

step-by-step explanation: