Arocket is launched from atop a 105-foot cliff with an initial velocity of 156 ft/s. the height of the rocket above the ground at time t is given by h = –16t2 + 156t + 105. when will the rocket hit the ground after it is launched? round to the nearest tenth of a second.

4.9 s
9.8 s
0.6 s
10.4 s

The correct option is 4. The rocket will hit the ground after 10.4 s.

Step-by-step explanation:

The given function is

Where, h is height of the rocket above the ground at time t.

The rocket will hit the ground, when h=0.

Using quadratic formula

The time can  not negative, therefore after 10.382 second the rocket will hit the ground.

Therefore the correct option is 4. The rocket will hit the ground after 10.4 s.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes