A cannon ball is shot upwards from a height of 5 feet at a velocity of 40 feet per second the equation h(t) = -16^2 + 40t + 5 how long did it take for the cannon ball to hit the ground ?
what was the maximum height of the cannon ball ?
how long did it take for the cannon ball to reach the maximum height ?
how high was the cannon ball after 1.4 seconds ?

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x