In a sequence of numbers, a4=12, a5=14, a6=16, a7=18, and a8=20. Which equation can be used to find the nth term of the sequence, an?

a) an=2n+4

b) an=2n+12

c) an=3n

d) an=3n+12

I'm pretty sure it's a, but I just wanna check if I did the work right!

you are right, it's a)❤

Step-by-step explanation:

a4=12---> put the formula in it

2×4+4=12

a5=14---> 2×5+4=14

a6=16---> 2×6+4=16

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hope it helps❤

b and c

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct