Tangent line of f(x) = sec x @ (pi/3, 2)

The derivitive of sec(x) is sec(x)tan(x)

find the slope at pi/3

sec(pi/3)=2
tan(pi/3)=√3

sec(x)tan(x) at x=pi/3 is 2√3

for slope=m and a point is (x1,y1)
the equation is
y-y1=m(x-x1)
slope=2√3
point=(pi/3,2)

equation is
y-2=2√3(x-pi/3)

The answer is option c.

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