Use the following diagram and information to answer the question. Given: ABCD is a parallelogram. △ABC≅△BCD
Julie wants to prove that ABCD is a square. She uses properties of congruent triangles and parallelograms to prove that ∠A≅∠B≅∠C≅∠D. She must also show that AB≅BC≅CD≅DA to prove ABCD is a square.
What else must Julie do to prove ABCD is a square?
a) Julie can use properties of congruent triangles to show that AB¯≅CD and AD≅BC. Then she can use the definition of parallelogram to show AB≅BC.
b) Julie can use properties of congruent triangles to show that AB≅BC and BC≅CD. Then she can show BC≅AD because opposite sides of a parallelogram are congruent.
c) Julie can use the definition of a parallelogram to show that AB≅BC and BC≅CD. Then she can use the definition of congruent triangles to show BC≅AD.
d)Julie can use properties of congruent triangles to show that AC≅BD. Then she can use the definition of parallelogram to show BC≅AD.

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

students group

step-by-step explanation:

a person who   joins a party or a seminar can explain his feelings about that particular occasion better more than anyone else.

as bella managed a show for the students in the school and invited students to watch that show

hence

students group will be the best group to survey to find this information

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.