The figure shown is made up of a triangle and a square. The perimeter of the figure is 56 inches. Complete the description to find the area of the figure.
10 in.
8 in.
10 in.
The total length of three sides of the square is in., so the side length of the square is
in. The area of the triangle is in?, and the area of the square is in?, so the total area is

Image of figure is missing so i have attached it.

The total length of three sides of the square = 36 in

Side length of square = 12 in

A_triangle = 48 in²

Area of square = 144 in²

Total area of figure = 192 in²

Step-by-step explanation:

Total perimeter = 56 inches

Let the side of the square be s.

Thus, perimeter of the 3 sides of the square = 3s

Therefore, adding all the external sides of the figure, we have;

3s + 10 + 10 = 56

3s + 20 = 56

3s = 56 - 20

3s = 36

s = 36/3

s = 12

Area of triangle is given by the formula;

A_triangle = ½bh

Where;

b is base

h is height

Thus;

A_triangle = ½ × 12 × 8

A_triangle = 48 in²

Area of square = 12 × 12 = 144 in²

Total area of figure = 144 + 48 = 192 in²

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100