A traffic camera sits on top of a tower that has a height of 39 ft. The angles of depression of a car on a straight road at the same level as that of the base of the tower and on the same side of the tower are 31°. Calculate the the distance between the base of the poll and the car. Round to the nearest tenth of a foot. *

48ft

Step-by-step explanation:

Consider ∆ACD

tan25 = 50/AC

AC  = 50/tan25 = 50/0.4663 = 107.2 ft

Consider ∆BCD

tan40 = 50/BC

AC  = 50/tan40 = 50/0.8391 = 59.6 ft

AB = AC – BC = 107.2 – 59.6 = 48 ft

The distance between the two cars is

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3