F(x)= (x+2)^2 -1
find x intercept
find y intercept
find vertex

The x intercept occurs when y = 0.

0=(x+2)^2 - 1
1=(x+2)^2

Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.

1=x+2
-1=x

The x intercept is -1.

The y intercept occurs when x=0.

y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3

The y intercept is 3.

Now, to find the vertex...

This parabola is currently in a format called the vertex form, which is:

f(x) = (x-h)^2 + k

where (h, k) is the vertex.

Therefore, the vertex is (-2, -1).

No i refuse to tell you the answer but the estimate is 10

Ithink you’re answering is d