A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. You scored a 625. Calculate your z-score to the nearest hundredth (i. e. 2 decimal places). z=

1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean = 500 and a standard deviation =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score =

Z-score =

⇒ Z-score =

⇒Z-score =1.25

Therefore , the required z-score = 1.25

for b its (t) and c its (d)

step-by-step explanation: