A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100. You scored a 625. Calculate your z-score to the nearest hundredth (i. e. 2 decimal places). z=

The required z-score = 1.25

Step-by-step explanation:

Let x be a random variable that denotes the scores in the exam.

The formula for z-score =

As per given, we have

X= 625, mean=500, standard deviation = 100

Z-score =

i.e. Z-score =

i.e. Z-score =1.25

Hence, the required z-score = 1.25

< 6 cm to > 26 cm i believe

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)