"in the 45°-45°-90° triangle above, r = 10. find the other two lengths.
a) p = 3√2, q = 10√2
b) p = 5√2, q = 2√2
c) p = 5, q = 8
d) p = 6√3, q = 8√6
(will draw picture below)"

We are given a right triangle that has angles of 45°-45°-90°. This would indicate that the triangle is an isosceles type. We can use some trigonemetric functions to solve for the other legs. We do as follows:

sin 45 = p / 10

p = 5√2

cos 45 = q /10

q = 5√2

Hope this answers the question. Have a nice day.

goog may have it for you

(3x-8) or (3x+8)

step-by-step explanation: