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Mathematics, 13.04.2021 19:10 tayler6289

At liftoff, the space shuttle Discovery has a constant acceleration of 16.4 feet per second squared and an initial velocity of 1341 feet per second due to the rotation of Earth. The distance Discovery has traveled t seconds after
liftoff is given by the equation h=8.2t^2 +1341t. How long after liftoff has Discovery traveled 40,000 feet? Round
your answer to the nearest tenth.

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At liftoff, the space shuttle Discovery has a constant acceleration of 16.4 feet per second squared...
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