This is the third time and i a really annoyed as i am having my time wasted and points plz help me

A) 20.9 ; B) 34years

Step-by-step explanation:

Given the following :

AGE (X) - - - - - - - 19 - -20 - - - 21 - - - 22 - - - 23

FREQUENCY (F) - 2 - - 3 - - - - 1 - - - - 4 - - - - 1

A)

MEAN(X) = [AGE(X) × FREQUENCY (F)] ÷ SUM OF FREQUENCY

F*X = [(19 * 2) + (20 * 3) + ( 21 * 1)+(22 * 4)+(23 * 1)]

= 38 + 60 +21 + 88 + 23 = 230

SUM OF FREQUENCY = 2 + 3 + 1 + 4 + 1= 11

MEAN(X) = 230 / 11

X = 20.9

B)

WHEN A NEW PLAYER WAS ADDED :

MEAN (X) = 22

Let age of new player = y

Sum of Ages = 19 + 19 +20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 + y

Number of players = 11 + 1 = 12

Mean(x) = sum of ages / number of players

New mean (x) = 22

x = (230 + y) / 12

22 = (230 + y) / 12

Cross multiply

264 = 230 + y

y = 264 - 230

y = 34 years

a) 21.0

b) 5yrs

Step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

im alright what do you need

step-by-step explanation: