Prove quadrilateral MATH, M (-4,-1) A(-3,2). T(3,0), H(2-3) is a rectangle

Since MA ≠ TH, hence MATH is not a rectangle

Step-by-step explanation:

To prove that quadrilateral MATH, M (-4,-1) A(-3,2). T(3,0), H(2-3) is a rectangle, we need to get the length of each sides and show that MA =TH and MH = TA

For MA:

M (-4,-1) A(-3,2)

MA = √(2+1)²+(3+4)²

MA = √(3)²+(7)²

MA = √9+49

MA =√58

For TH:

T(3,0), H(2-3)

TH = √(-3-0)²+(2-3)²

TH = √(-3)²+(-1)²

TH = √9+1

TH =√10

For TH:

M(-4,-1), H(2-3)

MH = √(-3+1)²+(2+4)²

MH = √(-2)²+(6)²

MH = √4+36

MH =√40

For TA:

T(3,0), A(-3,2)

TA = √(2-0)²+(-3-3)²

TA = √(2)²+(-6)²

TA = √4+36

TA =√40

Since MA ≠ TH, hence MATH is not a rectangle

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step-by-step explanation: