One earthquake has MMS magnitude 3.9. If a second earthquake has 120 times as much energy (earth movement) as the first, find the magnitude of the second quake.

The right answer is "5.9". A further solving is provided below.

Step-by-step explanation:

The given values are:

Initial Magnitude,

M₁ = 3.9

Let Second magnitude be M₂.

Now,

⇒  

On substituting the values, we get

⇒  

On putting the value of "log 120", we get

⇒  

On adding "3.9" both sides, we get

⇒  

⇒                    

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: